Magnus O.

Nice then Just the one EG model which doesn't have ECU-controlled fuel injected engine, and I got that ignition But, yesterday I applied 'surgery' to the thing, and found the reluctor / contactor; disassembled further, until I got the Igniter Unit, which has a coil where the axis of the reluctor rotates through - I opened this coil up and was lucky to find the terminals where the coil connects to. These will then be the terminals where I have to apply a minimum voltage pulse to, in order to trigger a spark. I can't see why this wouldn't work One thing though is that the voltage will have to be very little.

Hm, not much replies Let me otherwise rephrase the question with the info I now have: How much volt would a magnetic pickup (reluctor / stator) generator towards the Igniter Unit? I expect this to be minimal; somewhere on the web I read in the range of 50 mV to 200 mV (0.2V), do you reckon this is correct, or can I apply a higher voltage when I want to mimic this signal towards the Igniter Unit?

Hi all, Yes, I know this is only MA/MB/MC-series, but I realised there live some experts here which will certainly know the answer on my question. I've been looking for an ignition for an experiment; this ignition should have been ECU-controlled, just like my MB-series ignition. Unfortunately, the guy from who I bought it sent me an ignition from an EG; I knew that, but didn't know it came from an EG DX (which has a D13B2 engine); and this engine has an (electric) carburator...!! The EG I used to own (D15B2) has fuel injection, so also ECU-controlled ignition. Before buying this item I wasn't aware it came from an EG DX 1.3, and also checked on our Dutch forum to confirm EG's use ECU-controlled ignition - no one realised there's also the 1.3 carburated engine, from which I now got the ignition...!! To be short: my experiment consists of a pulse generator, which was meant to mimic the ECU's ignition control signal - this connected to any Honda ECU-controlled ignition (like MB series) would then allow me to generate sparks - which I need for my experiment (plus it has to be as close to real life sparks in a car during driving as possible). The ignition which I now got (D4w90-03 4103 is the type nr on the side) only has two wires, and according to the electrical sheet which I found this is only the 12V supply and the tachometer return... I opened it op and saw it has some kind of extra rotating 4-blade thing below the rotor, which remind me about the old contactors used in classic carburators. This is called a reluctor and stator I've learned now. It even has a mechanical 'ignition delayer/advancer' based on vacuum...! The circuit also explains it has a ignition control unit, which is driven by this 4-blade fin/rotor thing which slightly touches two terminals when rotating (they seem magnetic). The ignition control unit on his turn switches the primary coil. Now my question is: How does this particular ignition control unit work? Is it a transistor like in the more recent Ignition Control Modules, controlled by a small voltage from the magnetic reluctor/stator? I.e. does the rotating 4-blade thing generate some kind of low voltage pulse, which may be identical to the ECU pulse in a more recent ignition, which on its turn drives a transistor to switch the higher-current voltage powering the primary coil? I need to be able to let my pulse generator drive this ignition, like I would drive the more recent ignitions which are ECU-controlled. The pulse generator (like the ECU does too) can only generate low voltage low current signals (upto 15V max if necessary, but low amps - so just signalling) I do hope so!!! Otherwise this ignition is useless for my experiment... Thank you so much for your input!

You have a VTi-S?? Nice !

Do you have 1.5L or 1.8L? 1.5L standard is 185/60 R14 = 1.81 meter outline. 1.8L standard is 195/55 R15 = 1.87 meter ouline. If you'd have 16 inch, then these are the outlines: 205/40 R16 = 1.79 meter outline (nearly perfect match for 1.5L engines) = 2 cm off per rotation 205/45 R16 - 1.86 meter outline (nearly perfect match for 1.8L engines) = 1 cm off per rotation @Dave: 195/50 R16 = 1.89 meter outline = pretty allright for 1.8L but far out for 1.5L engines = 8 cm per rotation (!) See http://www.timloto.org/formules/bandhoogte.html although in Dutch